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- [轉貼]How to pass a variable in a curl command in shell scripting
- How to pass a variable in a curl command in shell scripting
I have a curl command:
curl -u ${USER_ID}:${PASSWORD} -X GET 'http://lppma670.gso.aexp.com:8080/rest/job-execution/job-details/${job_id}'
The variable job_id has a value in it, say, 1160. When I execute the curl command in shell it gives me the following error:
{"message":"Sorry. An unexpected error occured.", "stacktrace":"Bad Request. The request could not be understood by the server due to malformed syntax."}
If I pass the number '1160' directly in the command, as shown below, the curl command works.
curl -u ${USER_ID}:${PASSWORD} -X GET 'http://lppma670.gso.aexp.com:8080/rest/job-execution/job-details/1160'
Can someone please help me out? I wanna be able to pass the value of the variable in the curl command.
When using variables in shell, you can only use doubles quotes, not single quotes : the variables inside single quotes are not expanded. Learn the difference between ' and " and `. See http://mywiki.wooledge.org/Quotes and http://wiki.bash-hackers.org/syntax/words
Double quotes while assigning the value 1160 to job_id? You mean like this? "job_id=1160". And then call it inside the curl command using ${job_id}?
yes : job_id=1160;
curl -u ${USER_ID}:${PASSWORD} -X GET "http://lppma670.gso.aexp.com:8080/rest/job-execution/job-details/${job_id}"
原文出處：bash - How to pass a variable in a curl command in shell scripting - Stack Overflow
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[轉貼]curl 指令用法 (冷日