茫茫網海中的冷日 - 對這文章發表回應
茫茫網海中的冷日
         
茫茫網海中的冷日
發生過的事,不可能遺忘,只是想不起來而已!
 恭喜您是本站第 1671409 位訪客!  登入  | 註冊
主選單

Google 自訂搜尋

Goole 廣告

隨機相片
IMG_60D_00006.jpg

授權條款

使用者登入
使用者名稱:

密碼:


忘了密碼?

現在就註冊!

對這文章發表回應

發表限制: 非會員 可以發表

發表者: 冷日 發表時間: 2022/6/24 2:23:18

Removing all duplicates from a List in Java

Last modified: September 8, 2021

1. Introduction

In this quick tutorial, we're going to learn how to clean up the duplicate elements from a List. First, we'll use plain Java, then Guava, and finally, a Java 8 Lambda-based solution.

This tutorial is part of the Java – Back to Basic” series here on Baeldung.

2. Remove Duplicates From a List Using Plain Java

We can easily remove the duplicate elements from a List with the standard Java Collections Framework through a Set:


public void 
givenListContainsDuplicates_whenRemovingDuplicatesWithPlainJava_thenCorrect() {
List<Integer> listWithDuplicates = Lists.newArrayList(5, 0, 3, 1, 2, 3, 0, 0);
List<Integer> listWithoutDuplicates = new ArrayList<>(
new HashSet<>(listWithDuplicates));
assertThat(listWithoutDuplicates, hasSize(5));
assertThat(listWithoutDuplicates, containsInAnyOrder(5, 0, 3, 1, 2));
}

As we can see, the original list remains unchanged.

In the example above, we used HashSet implementation, which is an unordered collection. As a result, the order of the cleaned-up listWithoutDuplicates might be different than the order of the original listWithDuplicates.

If we need to preserve the order, we can use LinkedHashSet instead:


public void 
givenListContainsDuplicates_whenRemovingDuplicatesPreservingOrderWithPlainJava_thenCorrect() {
List<Integer> listWithDuplicates = Lists.newArrayList(5, 0, 3, 1, 2, 3, 0, 0);
List<Integer> listWithoutDuplicates = new ArrayList<>(
new LinkedHashSet<>(listWithDuplicates));
assertThat(listWithoutDuplicates, hasSize(5));
assertThat(listWithoutDuplicates, containsInRelativeOrder(5, 0, 3, 1, 2));
}

3. Remove Duplicates From a List Using Guava

We can do the same thing using Guava as well:


public void 
givenListContainsDuplicates_whenRemovingDuplicatesWithGuava_thenCorrect() {
List<Integer> listWithDuplicates = Lists.newArrayList(5, 0, 3, 1, 2, 3, 0, 0);
List<Integer> listWithoutDuplicates
= Lists.newArrayList(Sets.newHashSet(listWithDuplicates));
assertThat(listWithoutDuplicates, hasSize(5));
assertThat(listWithoutDuplicates, containsInAnyOrder(5, 0, 3, 1, 2));
}

Here also, the original list remains unchanged.

Again, the order of elements in the cleaned-up list might be random.

If we use the LinkedHashSet implementation, we'll preserve the initial order:


public void 
givenListContainsDuplicates_whenRemovingDuplicatesPreservingOrderWithGuava_thenCorrect() {
List<Integer> listWithDuplicates = Lists.newArrayList(5, 0, 3, 1, 2, 3, 0, 0);
List<Integer> listWithoutDuplicates
= Lists.newArrayList(Sets.newLinkedHashSet(listWithDuplicates));
assertThat(listWithoutDuplicates, hasSize(5));
assertThat(listWithoutDuplicates, containsInRelativeOrder(5, 0, 3, 1, 2));
}

4. Remove Duplicates From a List Using Java 8 Lambdas

Finally, let's look at a new solution, using Lambdas in Java 8. We'll use the distinct() method from the Stream API, which returns a stream consisting of distinct elements based on the result returned by the equals() method.

Additionally, for ordered streams, the selection of distinct elements is stable. This means that for duplicated elements, the element appearing first in the encounter order is preserved:


public void 
givenListContainsDuplicates_whenRemovingDuplicatesWithJava8_thenCorrect() {
List<Integer> listWithDuplicates = Lists.newArrayList(5, 0, 3, 1, 2, 3, 0, 0);
List<Integer> listWithoutDuplicates = listWithDuplicates.stream()
.distinct()
.collect(Collectors.toList());
assertThat(listWithoutDuplicates, hasSize(5));
assertThat(listWithoutDuplicates, containsInAnyOrder(5, 0, 3, 1, 2));
}

There we have it, three quick ways to clean up all the duplicate items from a List.

5. Conclusion

In this article, we demonstrated how easy it is to remove duplicates from a list using plain Java, Google Guava, and Java 8.

The implementation of all of these examples and snippets can be found in the GitHub project. This is a Maven-based project, so it should be easy to import and run.


原文出處:Removing all duplicates from a List in Java | Baeldung
內容圖示
url email imgsrc image code quote
樣本
bold italic underline linethrough   












 [詳情...]
validation picture

注意事項:
預覽不需輸入認證碼,僅真正發送文章時才會檢查驗證碼。
認證碼有效期10分鐘,若輸入資料超過10分鐘,請您備份內容後,重新整理本頁並貼回您的內容,再輸入驗證碼送出。

選項

Powered by XOOPS 2.0 © 2001-2008 The XOOPS Project|