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DB研討會 : [轉貼]USE MULTIPLE LEFT JOIN

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冷日
(冷日)
Webmaster
  • 註冊日: 2008/2/19
  • 來自:
  • 發表數: 15771
[轉貼]USE MULTIPLE LEFT JOIN
USE MULTIPLE LEFT JOIN

Is it possible to use multiple left join in sql query? if not then whats the solution?
    LEFT JOIN
        ab
    ON
        ab.sht = cd.sht

i want to add to atach one more query like this to it? will it work?
    LEFT JOIN
        ab AND aa
    ON
        ab.sht = cd.sht
           AND
                    aa.sht = cc.sht

Will this work?

--------------------------------------------------------------------------------

Yes it is possible. You need one ON for each join table.
LEFT JOIN ab
  ON ab.sht = cd.sht
LEFT JOIN aa
  ON aa.sht = cd.sht

Incidentally my personal formatting preference for complex SQL is described in http://bentilly.blogspot.com/2011/02/sql-formatting-style.html. If you're going to be writing a lot of this, it likely will help.

--------------------------------------------------------------------------------

Yes, but the syntax is different than what you have
SELECT
    <fields>
FROM
    <table1>
    LEFT JOIN <table2>
        ON <criteria for join>
        AND <other criteria for join>
    LEFT JOIN <table3>
        ON <criteria for join>
        AND <other criteria for join>


--------------------------------------------------------------------------------

The required SQL will be some like:-
SELECT * FROM cd
LEFT JOIN ab ON ab.sht = cd.sht
LEFT JOIN aa ON aa.sht = cd.sht
....

Hope it helps.

--------------------------------------------------------------------------------

You have two choices, depending on your table order
create table aa (sht int)
create table cc (sht int)
create table cd (sht int)
create table ab (sht int)

-- type 1
select * from cd
inner join cc on cd.sht = cc.sht
LEFT JOIN ab ON ab.sht = cd.sht
LEFT JOIN aa ON aa.sht = cc.sht

-- type 2
select * from cc
inner join cc on cd.sht = cc.sht
LEFT JOIN ab
LEFT JOIN aa
ON aa.sht = ab.sht
ON ab.sht = cd.sht


原文出處:sql - USE MULTIPLE LEFT JOIN - Stack Overflow
冷日
(冷日)
Webmaster
  • 註冊日: 2008/2/19
  • 來自:
  • 發表數: 15771
[轉貼]Double LEFT JOIN
Double LEFT JOIN

I want to receive property name and units count and specails count. I have this query:
SELECT
  `property`.`property_name`,
  COUNT(unit_id) AS `units_count`,
  COUNT(special_id) AS `specials_count`
FROM `property`
  LEFT JOIN `property_unit` ON unit_property_id = property_id
  LEFT JOIN `property_special` ON special_property_id = property_id
WHERE (property_id = '1')
GROUP BY `property_id`
ORDER BY `property_name` ASC

But it is not working properly. If I have one of these left joins - it's ok, but if I have two, I get this result:
["property_name"] => string(11) "Rivers Edge"
["units_count"] => string(1) "2"
["specials_count"] => string(1) "2"

Specials count is 2 and units_count is 2, but units count is really '1'. How can I get correct counts for it?
P.S: for those who know Zend Framework:
$select->setIntegrityCheck(FALSE)
    ->from(
        'property',
        array(
            'property_name',
        )
    )
    ->joinLeft(
        'property_unit',
        'unit_property_id = property_id',
        array(
            'units_count' => 'COUNT(unit_id)'
        )
    )
    ->joinLeft(
        'property_special',
        'special_property_id = property_id',
        array(
            'specials_count' => 'COUNT(special_id)'
        )
    )
    ->group('property_id')
    ->order('property_name');


--------------------------------------------------------------------------------

Try this:
SELECT
  `property`.`property_name`,
  COUNT(distinct unit_id) AS `units_count`,
  COUNT(distinct special_id) AS `specials_count`
FROM `property`
  LEFT JOIN `property_unit` ON unit_property_id = property_id
  LEFT JOIN `property_special` ON special_property_id = property_id
WHERE (property_id = '1')
GROUP BY `property_id`
ORDER BY `property_name` ASC

EDIT:
You shouldn't always use distinct - it happens to be the right option in this case.
select count(fieldname) returns the number of times that fieldname is not null; select count(distinct fieldname) returns the number of distinct values of fieldname.
In the original query, property_unit and property_special aren't joined to each other, only to property - so for a single property that had 5 units and 7 specials, 35 rows would be returned; therefore count(unit_id) and count(special_id) would both return 35. Since there would be 5 distinct values of unit_id and 7 distinct values of special_id (because these fields uniquely identify their records), count(distinct ...) returns the correct values in these circumstances.

--------------------------------------------------------------------------------

Your SQL should be something like this:
SELECT
  `property`.`property_name`,
  COUNT(property_unit.unit_id) AS `units_count`,
  COUNT(property_special.special_id) AS `specials_count`
FROM `property`
  LEFT JOIN `property_unit` ON (property_unit.unit_property_id = property.property_id)
  LEFT JOIN `property_special` ON (property_special.special_property_id = property.property_id)
WHERE (property.property_id = '1')
GROUP BY `property.property_id`
ORDER BY `property.property_name` ASC


原文出處:sql - Double LEFT JOIN - Stack Overflow
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